Optimal. Leaf size=81 \[ \frac{5}{4 a^2 d (\cos (c+d x)+1)}-\frac{1}{4 a^2 d (\cos (c+d x)+1)^2}+\frac{\log (1-\cos (c+d x))}{8 a^2 d}+\frac{7 \log (\cos (c+d x)+1)}{8 a^2 d} \]
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Rubi [A] time = 0.060841, antiderivative size = 81, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {3879, 88} \[ \frac{5}{4 a^2 d (\cos (c+d x)+1)}-\frac{1}{4 a^2 d (\cos (c+d x)+1)^2}+\frac{\log (1-\cos (c+d x))}{8 a^2 d}+\frac{7 \log (\cos (c+d x)+1)}{8 a^2 d} \]
Antiderivative was successfully verified.
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Rule 3879
Rule 88
Rubi steps
\begin{align*} \int \frac{\cot (c+d x)}{(a+a \sec (c+d x))^2} \, dx &=-\frac{a^2 \operatorname{Subst}\left (\int \frac{x^3}{(a-a x) (a+a x)^3} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{a^2 \operatorname{Subst}\left (\int \left (-\frac{1}{8 a^4 (-1+x)}-\frac{1}{2 a^4 (1+x)^3}+\frac{5}{4 a^4 (1+x)^2}-\frac{7}{8 a^4 (1+x)}\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{1}{4 a^2 d (1+\cos (c+d x))^2}+\frac{5}{4 a^2 d (1+\cos (c+d x))}+\frac{\log (1-\cos (c+d x))}{8 a^2 d}+\frac{7 \log (1+\cos (c+d x))}{8 a^2 d}\\ \end{align*}
Mathematica [A] time = 0.186381, size = 83, normalized size = 1.02 \[ \frac{\sec ^2(c+d x) \left (10 \cos ^2\left (\frac{1}{2} (c+d x)\right )+4 \cos ^4\left (\frac{1}{2} (c+d x)\right ) \left (\log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )+7 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )-1\right )}{4 a^2 d (\sec (c+d x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.076, size = 72, normalized size = 0.9 \begin{align*} -{\frac{1}{4\,d{a}^{2} \left ( \cos \left ( dx+c \right ) +1 \right ) ^{2}}}+{\frac{5}{4\,d{a}^{2} \left ( \cos \left ( dx+c \right ) +1 \right ) }}+{\frac{7\,\ln \left ( \cos \left ( dx+c \right ) +1 \right ) }{8\,d{a}^{2}}}+{\frac{\ln \left ( -1+\cos \left ( dx+c \right ) \right ) }{8\,d{a}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.19077, size = 100, normalized size = 1.23 \begin{align*} \frac{\frac{2 \,{\left (5 \, \cos \left (d x + c\right ) + 4\right )}}{a^{2} \cos \left (d x + c\right )^{2} + 2 \, a^{2} \cos \left (d x + c\right ) + a^{2}} + \frac{7 \, \log \left (\cos \left (d x + c\right ) + 1\right )}{a^{2}} + \frac{\log \left (\cos \left (d x + c\right ) - 1\right )}{a^{2}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.19867, size = 297, normalized size = 3.67 \begin{align*} \frac{7 \,{\left (\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) +{\left (\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 10 \, \cos \left (d x + c\right ) + 8}{8 \,{\left (a^{2} d \cos \left (d x + c\right )^{2} + 2 \, a^{2} d \cos \left (d x + c\right ) + a^{2} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\cot{\left (c + d x \right )}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec{\left (c + d x \right )} + 1}\, dx}{a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32623, size = 158, normalized size = 1.95 \begin{align*} \frac{\frac{2 \, \log \left (\frac{{\left | -\cos \left (d x + c\right ) + 1 \right |}}{{\left | \cos \left (d x + c\right ) + 1 \right |}}\right )}{a^{2}} - \frac{16 \, \log \left ({\left | -\frac{\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1 \right |}\right )}{a^{2}} - \frac{\frac{8 \, a^{2}{\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac{a^{2}{\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}}{a^{4}}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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